## SOLUTION:

Let’s break down the solution to this interesting puzzle. We’ll start by finding the value of the items in each equation carefully.

First, let’s figure out the value of one clock using the first equation:

9’o clock + 9’o clock + 3’o clock = 9 + 9 + 3 = 21.

Therefore, one clock equals 1.

Next, on to equation two. Here, three calculators are equal to 30. So, we find out that one calculator is equal to 10.

Now, it’s important to note that the value of the calculator actually depends on the sum of the numbers inside it. For example, the numbers inside one calculator are 1 + 2 + 3 + 4, which equals 10.

Moving forward to equation three — we have:

1 Bulb + 1 Bulb – 1 Bulb = 15.

By cancelling out the bulbs using addition and subtraction, we find that one bulb with five lights inside equals 15. Therefore, one bulb with one light equals 3.

So, a bulb with four lights equals 4 times 3, which is 12.

Now onto the final equation:

The equation involves 9’o clock + Calculator (1+2+2+4) x 3 bulbs (with four light rays each).

Converting the final equation into numbers, it becomes: 9 + (1+2+2+4) x 3(12).

This translates to:

9 + 9 x 36 = 9 + 324 = 333.

So the final answer is 333.